How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
In the figure, O is the centre of circle PQRS and PS//RT. If PRT = 135, then PSO is
67\(\frac{1}{2}\)o
22\(\frac{1}{2}\)o
33\(\frac{1}{2}\)o
45o
90o
Correct answer is D
< R = 180o - 45o (sum of angles on a straight line)
< R = < P = 45o (corresponding angles)
< PSO = < P = 45o (\(\bigtriangleup\)PSO is a right angle)
In the figure, TSP = PRQ, QR = 8cm, PR = 6cm and ST = 12cm. Find the length SP
4cm
16cm
9cm
14cm
Impossible, insufficient data
Correct answer is B
\(\frac{PQ}{6 + RT} = \frac{6}{12} = \frac{6}{PS}\)(Similar triangles)
\(\frac{6}{12} = \frac{8}{PS}\)
PS = \(\frac{12 \times 8}{6}\)
= 16cm
Find the x co-ordinates of the points of intersection of the two equations in the graph
1, 1
0, 4
0,0
4, 0
4, 9
Correct answer is D
If y = 2x + 1 and y = x2 - 2x + 1
then x2 - 2x + 1 = 2x + 1
x2 - 4x = 0
x(x - 4) = 0
x = 0 or 4
In the figure, determine the angle marked y
66o
110o
26o
70o
44o
Correct answer is A
From the diagram, < p = 44o, < Q = 70o
< y = 180o - (70 + 44o) = 66o
In the figure, QRS is a line, PSQ = 35o, SPR = 30o and O is the centre of the circle. Find OQP.
35o
30o
130o
25o
65o
Correct answer is D
< PSQ = 35o, < SPR = 30o
O is the centre of the circle, PRQ = 65o
< OQP = 90 - 65
= 25o