How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
30o 35'
30o 32'
15o 36'
10o
10o 42'
Correct answer is E
tan\(\theta\) = \(\frac{0.8}{2}\) = (0.4)
\(\theta\) = tan-1(0.4)
From the diagram, the inclination of the diagonal PR to the horizontal is 10o 42'
The figure FGHK is a rhombus. What is the value of angle X?
30o
90o
150o
120o
60o
Correct answer is D
< HKF = 60o, < KFG = 120o
< KFG = < KHG = x(opposite angles)
x = 120o
Which of the following equations represents the graph?
y = 1 + 2x + 3x2
y = 1 - 2x + 3x2
y = 1 + 2x - 3x2
y = 1 - 2x - 3x2
y = 3x2 + 2x - 1
Correct answer is E
The roots of the function are 1 and \(\frac{1}{3}\)
sum of roots = -1 + \(\frac{1}{3}\) = -\(\frac{2}{3}\)
product of roots = -1 x \(\frac{1}{3}\) = -\(\frac{1}{3}\)
x2 - (sum of roots)x + (product of roots) = 0
x2 + (-\(\frac{2}{3}\))x - (-\(\frac{1}{3}\)) = 0
x2 + \(\frac{2x}{3}\) - \(\frac{1}{3}\) = 0
3x2 + 2x - 1 = 0
66\(\frac{1}{2}\)o
62\(\frac{1}{2}\)o
125o
105o
65o
Correct answer is B
Angle subtended at any part of the circumference of the circle \(\frac{125^o}{2}\) at centre = 360o - 235o = 125o
\(\bar{PQR}\) = \(\frac{125}{2}\)
= 62\(\frac{1}{2}\)o
15
10
18
12
20
Correct answer is B
(2x - 24)° + (3x - 18)° + (2x + 12)° + (x + 12)° + x° = 360°
9x = 360° + 18°
x = \(\frac{378}{9}\)
= 42°, if x = 42°, then add maths = \(\frac{2x - 42}{360}\) x 60
= \(\frac{2 \times 42 - 24}{360}\) x 60
= \(\frac{84 - 24}{6}\)