How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
155km/hr
50km/hr
40km/hr
124km/hr
84km/hr
Correct answer is E
Distance = 155 - 50 = 105km
Time = 75mins
= \(\frac{75}{60}\)hr = \(\frac{5}{4}\)hr
Average speed = \(\frac{Distance}{time}\) = \(\frac{105}{\frac{5}{4}}\)
= \(\frac{105 \times 4}{5}\)
= 84km\h
In the diagram, angle QPR = 90o, angle PSR = 90o and PR = 5 units. Find the length of QS.
5 tan 25o sin 65o
5 cos 25o sin 65o
5 tan 25o cos 65o
cos 25o cos 65o
5 cosec 25o
Correct answer is C
From \(\bigtriangleup\)QPR, < R = 180o - (25o + 90o)
180o - 115o = 65o
From \(\bigtriangleup\)PSQ, Sin 65o = \(\frac{QPR}{hyp}\) = \(\frac{PS}{5}\)
PS = 5 sin 65o
From \(\bigtriangleup\)PSR, tan = \(\frac{OPP}{adj}\) = \(\frac{PS}{QS}\)
but PS = 5 sin 65o
QS tan 25o = PS
QS tan 25o = 5 sin 65o
QS = \(\frac{5 sin 65^o}{tan 25^o}\)
= 5 tan 25o cos 65o
In the figure, WU//YZ, WY//YZ = 12cm, VZ = 6cm, XU = 8cm. Determine the length of WU.
1cm``3cm
6cm
2cm
4cm
Correct answer is D
From similar triangle, \(\frac{x}{6}\) = \(\frac{8}{12}\)
12x = 48
x = \(\frac{48}{12}\)
= 4
12cm2
28\(\frac{1}{2}\)cm2
16cm2
10cm2
6cm2
Correct answer is E
Area of the triangle XYZ = \(\frac{1}{2}\)bh = \(\frac{1}{2}\)ZY x XY
= \(\frac{1}{2}\) x 3 x 4
= 6cm2.
In the figure, find x in terms of a, b and c.
a + b + c
180o - (a + b + c)
a - b - c
a + b
a + c
Correct answer is A
180 - x + a + b + c
= 180(sum of interior angle in triangle)
a + b + c = x.