How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
In the figure, find the area of XYZW
60cm2
54cm2
36cm2
54\(\sqrt{2}\)cm2
27\(\sqrt{2}\)cm2
Correct answer is C
Average of trapezium XYZW = \(\frac{1}{2}\)(a + b)h from rt < YDZ,
h = 8 sin 30º
area = \(\frac{1}{2}\)(10 + 8)4
= 8 x \(\frac{1}{2}\) = 4
\(\frac{1}{2}\)(18) x 4
= 36cm2
50o
75o
35o
115o
30o
Correct answer is C
< WYT = \(\frac{180 - 30}{2}\)
= \(\frac{150}{2}\)
= 75o(base angles of isosceles D)
YXW = 75 - 40 = 35o(Exterior angle is equal to sum of interior angles)
Find the area of the shades segments in the figure
\(\sqrt{3}\)
4 \(\pi - \sqrt{3}\)
-\(\frac{2}{3} \pi\)
\(\frac{2\pi}{3}\) -3
Correct answer is D
Area of section = \(\frac{60^o}{360^o}\) x 11r2
= \(\frac{60}{360} \times \pi \times 2^2\)
= \(\frac{1}{6}\) x 4
= \(\frac{4\pi}{6}\)
= \(\frac{2\pi}{3}\)
Area of triangle = \(\frac{1}{2x}\)
= 2 x 28.......60
Segment Area = Area of section - Area of triangle
= \(\frac{2\pi}{3}\) -3
\(\frac{1}{2}\)
\(\frac{4}{\sqrt{3}}\)
\(\sqrt{3}\)
4\(\sqrt{3}\)
Correct answer is B
No explanation has been provided for this answer.
In the figure, PS = SR and Rx is a tangent to the circle at R, < QRX is equal to 72o. Find angle SPR
20o
36o
72o
30o
15o
Correct answer is B
XRQ = RSQ (Alternate segment)
s = 72o
(80o - 72o = 180o)
a + b + c = 190o = 2b + c = 180o
2b + 108 = 180o
2b = 72o
b = 36o