How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
81
27
\(\frac{1}{9}\)
\(\frac{1}{27}\)
\(\frac{1}{81}\)
Correct answer is A
\(x \propto \frac{1}{y}\)
\(x = \frac{k}{y}\)
\(y \propto t^{2}\)
\(y = ct^{2}\)
k and c are constants.
\(x = \frac{k}{ct^{2}}\)
Let \(\frac{k}{c} = d\) (a constant)
\(x = \frac{d}{t^{2}}\)
\(1 = \frac{d}{3^{2}} \implies d = 9\)
\(\therefore x = \frac{9}{t^{2}}\)
\(x = 9 \div (\frac{1}{3})^{2} \)
= \( 9 \div \frac{1}{9} = 9 \times 9 = 81\)
30 years
6 years
9 years
3 years
1 year
Correct answer is D
1st 30 pupils at average age of 15.3 yrs. give total age of 15.3 x 30 = 459yrs 2nd group of 30 pupils at average age of 15.2 yrs give total age of 15.2 x 30 = 456yrs Difference in age = 459 - 456 = 3 yrs
10:3
1:100
3:1
5:2
Correct answer is A
The distinct sectors in the same circle substend 100o and 30o respectively at the centre of the circle. Their corresponding arcs are in ratio 100:30 = 10:3
A variable y is inversely proportional to x2, when y = 10, x = 2. What is y when x = 10?
2
4
100
0.4
0.1
Correct answer is D
y \(\alpha\) \(\frac{1}{x^2}\)
y = \(\frac{k}{x^2}\)
k = x2y
= (2)2 x 10
= 40
y = \(\frac{40}{x^2}\)
= \(\frac{40}{(10)^2}\)
= \(\frac{40}{100}\)
= 0.4
2cm
8cm
4cm
2\(\sqrt{3}\)cm
16cm
Correct answer is D
\(\frac{x}{2}\) = sin60° = cos30°
x = 2 sino
= 2 x \(\frac{\sqrt{3}}{2}\)
= \(\sqrt{3}\)
length of the diagonal = 2 x \(\sqrt{2}\)
= 2\(\sqrt{3}\)