How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
The perpendicular bisector of UV
A circle with UV as radius
A line parallel to the line UV
A circle with the line UV as the diameter
Correct answer is D
No explanation has been provided for this answer.
Find the total surface area of solid cone of radius 2\(\sqrt{3}\)cm and slanting side 4\(\sqrt{3}\)
8\(\sqrt{3}\pi \)cm2
24\(\pi \)cm2
15\(\sqrt{3}\pi \)cm2
36\(\pi \)cm2
Correct answer is D
Total surface area of a solid cone
r = 2\(\sqrt{3}\)
= \(\pi r^2\) + \(\pi\)rH
H = 4\(\sqrt{3}\), \(\pi\)r(r + H)
∴ Area = \(\pi\)2\(\sqrt{3}\) [2\(\sqrt{3}\) + 4\(\sqrt{3}\)]
= \(\pi\)2\(\sqrt{3}\)(6\(\sqrt{3}\))
= 12\(\pi\) x 3
= 36\(\pi \)cm2
An arc of a circle of radius 6cm is 8cm long. Find the area of the sector
5\(\frac{1}{3}\)cm2
24cm2
36cm2
84cm2
Correct answer is B
Radius of the circle r = 6cm, Length of the arc = 8cm
Area of sector = \(\frac{\theta}{360}\) x \(\pi\)r2........(i)
Length of arc = \(\frac{\theta}{360}\) x 2\(\pi\)r........(ii)
from eqn. (ii) \(\theta\) = \(\frac{240}{\pi}\), subt. for \(\theta\) in eqn (i)
Area x \(\frac{240}{1}\) x \(\frac{1}{360}\) x \(\frac{\pi 6}{1}\)
= 24cm\(^2\)
69m
57m
51m
21m
Correct answer is C
QY = 452 + 242 = 2025 + 576
= 2601
QY = \(\sqrt{2601}\)
= 51
A regular polygon of n sides has 160o as the size of each interior angle. Find n
18
16
14
12
Correct answer is A
No explanation has been provided for this answer.