Mathematics questions and answers

Mathematics Questions and Answers

How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.

2,076.

A number of pencils were shared out among Bisi, Sola and Tunde in the ratio of 2 : 3 : 5 respectively. If Bisi got 5, how many were share out?

A.

15

B.

25

C.

30

D.

50

Correct answer is B

Let x r3epresent total number of pencils shared

B : S : T = 2 + 3 + 5 = 10

2 : 3 : 5

= \(\frac{2}{10}\) x y

= 5

2y =5

2y = 50

∴ y = \(\frac{50}{2}\)

= 25

2,077.

Udoh deposited N150.00 in the bank. At the end of 5 years the simple interest on the principal was N55.00. At what rate per annum was the interest paid?

A.

11%

B.

7\(\frac{1}{3}\)%

C.

5

D.

3\(\frac{1}{2}\)%

Correct answer is B

S.I = \(\frac{PTR}{100}\)

R = \(\frac{100}{PT}\)

\(\frac{100 \times 50}{150 \times 6}\) = \(\frac{22}{3}\)

= 7\(\frac{1}{3}\)%

2,078.

Simplify \(\frac{0.0324 \times 0.00064}{0.48 \times 0.012}\)

A.

3.6 x 102

B.

3.6 x 10-2

C.

3.6 x 10-3

D.

3.6 x 10-4

Correct answer is C

\(\frac{0.0324 \times 0.00064}{0.48 \times 0.012}\) = \(\frac{324 \times 10^{-4} \times 10^{-5}}{48 x 10^{-2} x 12 x 10^{-3}}\)

\(\frac{324 \times 64 \times 1 0^{-9}}{48 \times 12 \times 10^{-5}}\) = 36 x 10-4

= 3.6 x 10-3

2,079.

If P = 18, Q = 21, R = -6 and S = -4, Calculate \(\frac{(P- Q)^3 + S^2}{R^3}\) 

A.

\(\frac{-11}{216}\)

B.

\(\frac{11}{216}\)

C.

\(\frac{-43}{116}\)

D.

\(\frac{43}{116}\)

Correct answer is B

\(\frac{(P- Q)^3 + S^2}{R^3}\) = \(\frac{(18 - 21)^3 + (-4)^2}{(-6)^3}\)

= \(\frac{-27 + 16}{R^3}\)

= \(\frac{-11}{-216}\)

= \(\frac{11}{216}\)

2,080.

Three boys shared some oranges. The first received \(\frac{1}{3}\) of the oranges, the second received \(\frac{2}{3}\) of the remainder. If the third boy received the remaining 12 oranges, how many oranges did they share?

A.

60

B.

54

C.

48

D.

42

Correct answer is B

let x represent the total number of oranges shared, let the three boys be A, B and C respectively. A received \(\frac{1}{3}\) of x, Remainder = \(\frac{2}{3}\) of x . B received \(\frac{2}{3}\) of remainder (i.e.) \(\frac{2}{3}\) of x

∴ C received \(\frac{2}{3}\) of remainder (\(\frac{2}{3}\) of x) = 12

\(\frac{1}{3}\) x \(\frac{2x}{3}\) = 12

2x = 108

x = 54