How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
6.7, 6
7.6, 5
5.7, 87
34, 6
Correct answer is A
| No of defective(x) | No of boxes (f) | \(fx\) |
| 4 | 2 | 8 |
| 5 | 7 | 35 |
| 6 | 17 | 102 |
| 7 | 10 | 70 |
| 8 | 8 | 64 |
| 9 | 6 | 54 |
| \(\sum\) | 50 | 333 |
\(Mean = \frac{\sum fx}{\sum f}\)
= \(\frac{333}{50} = 6.66 \approxeq 6.7\)
The median is the average of the 25th and 26th position = 6.
76.8o and 25.2o
10.8o and 224.6o
112.4o and 72.0o
39.6o and 212.4o
Correct answer is D
Education = 11% = \(\frac{11}{100} \times 360° = 39.6°\)
Food = 59% = \(\frac{59}{100} \times 360° = 212.4°\)
Find the total area of the surface of a solid cylinder whose base radius is 4cm and height is 5cm
56\(\pi\) cm2
72\(\pi\) cm2
96\(\pi\) cm2
192\(\pi\) cm2
Correct answer is B
The total surface area of a cylinder = \(2\pi r (r + h)\)
= \(2 \pi (4) (4 + 5)\)
= \(8 \pi (9) = 72 \pi cm^{2}\)
0.30o
045o
060o
090o
Correct answer is C
tan \(\theta\) = \(\frac{60\sqrt{3}}{60}\) = \(\sqrt{3}\)
\(\theta\) = tan \(\frac{1}{3}\) = 60o
Bearing of y from x = 060o
If cos x = \(\sqrt{\frac{a}{b}}\) find cosec x
\(\frac{b}{\sqrt{b - a}}\)
\(\sqrt{\frac{b}{a}}\)
\(\sqrt{\frac{b}{b - a}}\)
\(\sqrt{\frac{b - a}{a}}\)
Correct answer is C
cosx = \(\sqrt{\frac{a}{b}}\)
y2 + \(\sqrt{(a)^2}\) = \(\sqrt{(b)^2}\) by pythagoras
y2 = b - a
∴ y = b - a
cosec x = \(\frac{1}{sin x}\) = \(\frac{1}{y}\)
\(\frac{b}{y}\) = \(\frac{\sqrt{b}}{\sqrt{b - a}}\)
= \(\sqrt{\frac{b}{b - a}}\)