b√b−a
√ba
√bb−a
√b−aa
Correct answer is C
cosx = √ab
y2 + √(a)2 = √(b)2 by pythagoras
y2 = b - a
∴ y = b - a
cosec x = 1sinx = 1y
by = √b√b−a
= √bb−a
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