How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Simplify \(\frac{5+\sqrt{7}}{3+\sqrt{7}}\)
17-√7
4-√7
15+√7
7-√7
Correct answer is B
\(\frac{5+\sqrt{7}}{3+\sqrt{7}}=\frac{5+\sqrt{7}}{3+\sqrt{7}}\times \frac{3-\sqrt{7}}{3-\sqrt{7}}\\
=\frac{(5+\sqrt{7})(3-\sqrt{7})}{3^2 - \sqrt{7}^2}\\
=\frac{15-5\sqrt{7}+3\sqrt{7}-7}{9-7}\\
=\frac{8-2\sqrt{7}}{2}\)
Factorize then divide by 2
\(=\frac{2(4-\sqrt{7}}{2}\\
=4-\sqrt{7}\)
If log\(_{10}\)2 = 0.3010 and log\(_{10}\)7 = 0.8451, evaluate log\(_{10}\)280
3.4471
2.4471
1.4471
1.4071
Correct answer is B
Log 2 = 0.3010, Log 7 = 0.8451
∴Log 280 = Log 28 x 10
= Log 7x4x10
=Log7 + Log4 + Log10
= Log7 + Log2\(^2\) + Log10
= Log7 + 2Log2 + Log10
= 0.8451 + 2(0.3010) + 1
= 0.8451 + 0.6020 + 1
= 2.4471
7/15
8/15
2/5
4/5
Correct answer is C
Let his allowance = y.
\(Books = \frac{y}{5}\)
\(Remainder: y - \frac{y}{5} = \frac{4y}{5}\)
\(Food: \frac{1}{2} \times \frac{4y}{5} = \frac{2y}{5}\)
\(Contingencies: \frac{4y}{5} - \frac{2y}{5} = \frac{2y}{5}\)
Therefore, he kept \(\frac{2}{5}\) of his allowance for contingencies.
N37,550
N40,400
N41,400
N42,400
Correct answer is C
C.P = N34000 + N2000 = N36000
Gain = 100 + 15 = 115%
S.P = \(\frac{115}{100}\times \frac{N3600}{1}\)
= N41400
Evaluate \(\frac{81.81+99.44}{20.09+36.16}\) correct to 3 significant figures.
6.24
3.22
2.78
2.13
Correct answer is B
\(\frac{81.81 + 99.44}{20.09 + 36.16}\\
=\frac{181.25}{56.25}\\
=\frac{18125}{5625}\\
\frac{29}{9}\\
=3\frac{2}{9}\\
≅ 3.22\)