How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Simplify \(7\frac{1}{12}-4\frac{3}{4}+2\frac{1}{2}\)
4
41/6
45/6
51/6
Correct answer is C
\(7\frac{1}{12}-4\frac{3}{4}+2\frac{1}{2}=5\left(\frac{1-9+6}{12}\right)\\
5\left(\frac{-2}{12}\right)\\
=4\left(\frac{12-2}{12}\right)\)
(carry one from 5 and call it 12)
\(4\frac{10}{12}\\
=4\frac{5}{6}\)
If 55\(_x\) + 52\(_x\) = 77\(_{10}\) find X
5
6
7
10
Correct answer is C
5 \(\times\) x\(^1\) + 5 \(\times\) x\(^0\) + 5 \(\times\) x\(^1\) + 2 \(\times\) x\(^0\) = 77
(change all to base 10)
5x + 5 + 5x + 2 = 77
10x + 7 = 77
10x = 77-7
10x = 70
x = 70/10
x = 7
3/10
1/5
1/6
1/10
Correct answer is B
Total possible outcome
12+18+x+30+2x+45 = 105+3x
∴105+3x = 150
3x = 150-105
3x = 45
x = 15
P(obtaining 5) = \(\frac{2x}{(105+3x)}But x= 15\\
=\frac{2(15)}{(105+3(15))}\\
=\frac{30}{(105+45)}\\
=\frac{30}{150}\\
=\frac{1}{5}\)
The probability of picking a letter T from the word OBSTRUCTION is?
1/11
2/11
3/11
4/11
Correct answer is B
OBSTRUCTION
Total possible outcome = 11
Number of chance of getting T = 2
P(picking T) = 2/11
Find the number of ways of selecting 6 out of 10 subjects for an examination
128
216
215
210
Correct answer is D
\(^{10}C_6 = \frac{10!}{(10-6)!6!}\\
=\frac{10!}{4!6!}\\
=\frac{10\times 9\times 8 \times 7 \times 6!}{4\times 3\times 2\times 1 \times 6!}\\
=210\)