How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
x2 - sin x + c
x2 + sin x + c
x2/2 - sin x + c
x2/2 + sin x + c
Correct answer is D
dy/dx = x + cos x
y = ∫(x + cos x)dx
y = 1/2x2 + sin x + C
Find the value of x for which the function 3x\(^3\) - 9x\(^2\) is minimum
zero
2
3
5
Correct answer is B
y = 3x\(^3\) - 9x\(^2\)
dy/dx = 9x\(^2\) - 18x
As dy/dx = 0
9x\(^2\) - 18x = 0
9x(x-2) = 0
9x = 0 which implies x = 0
x-2 = 0 implies x = 2
d2y/dx2 = 18x - 18
when x = 0
d2y/dx2 < 0 ∴ x is is minimum
when x = 2d\(^2\)y/dx\(^2\) = 18
∴ the value > 0 x is minimum
Differentiate (x2 - 1/x)2 with respect to x
4x2 - 4x - 2/x
4x2 - 2 + 2/x3
4x2 - 2 - 2/x3
4x2 - 3x + 2/x
Correct answer is C
y = (x2 - 1/x)2
y = (x2 - 1/x)(x2 - 1/x)
y = x4 - x - x + 1/x2
y = x4 - 2x + 1/x2
y= x4 - 2x + x-2
dy/dx = 4x2 - 2 - 2x-3
= 4x2 - 2 - 2/x3
y = x2 + 7x + 9
y = x2 + 7x - 18
y = x2 + 7x + 18
y = x2 + 14x + 11
Correct answer is B
dy/dx = 2x + 7
y = ∫2x + 7
y = x2 + 7x + C at (2,0)
0 = 22 + 7(2) + C
0 = 4 + 14 + C
0 = 18 + C
C = -18
∴ The equation is y = x2 + 7x - 18
For what of n is n+1C3 = 4(nC3)?
6
5
4
3
Correct answer is D
\(^{n+1}C_3 = 4(^nC_3)\\\frac{(n+1)!}{(n+1-3)!3!} = 4\left(\frac{n!}{(n-3)!3!}\right)\\\frac{(n+1)n!}{(n-2)(n-3)!}=4\left(\frac{n!}{n-3!}\right)\\=\frac{n+1}{n-2}=\frac{4}{1}\\n+1 = 4(n-2)\\n+1 = 4n-8\\-3n = -9\\\frac{-9}{-3}\\n=3\)