How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Find the value of x if \(\frac{\sqrt{2}}{x + \sqrt{2}}\) = \(\frac{1}{x - \sqrt{2}}\)
3\(\sqrt{2}\) + 4
3\(\sqrt{2}\) - 4
3 - 2\(\sqrt{2}\)
4 + 2\(\sqrt{2}\)
Correct answer is A
\(\frac{\sqrt{2}}{x + 2}\) = x - \(\frac{1}{\sqrt{2}}\)
x\(\sqrt{2}\) (x - \(\sqrt{2}\)) = x + \(\sqrt{2}\) (cross multiply)
x\(\sqrt{2}\) - 2 = x + \(\sqrt{2}\)
= x\(\sqrt{2}\) - x
= 2 + \(\sqrt{2}\)
x (\(\sqrt{2}\) - 1) = 2 + \(\sqrt{2}\)
= \(\frac{2 + \sqrt{2}}{\sqrt{2} - 1} \times \frac{\sqrt{2} + 1}{\sqrt{2} + 1}\)
x = \(\frac{2 \sqrt{2} + 2 + 2 + \sqrt{2}}{2 - 1}\)
= 3\(\sqrt{2}\) + 4
x > -\(\frac{1}{6}\)
x > 0
0 < x < 6
0 < x <\(\frac{1}{6}\)
Correct answer is A
\(\frac{1}{3x}\) + \(\frac{1}{2}\)x = \(\frac{2 + 3x}{6x}\) > \(\frac{1}{4x}\)
= 4(2 + 3x) > 6x = 12x\(^2\) - 2x = 0
= 2x(6x - 1) > 0 = x(6x - 1) > 0
Case 1 (-, -) = x < 0, 6x - 1 > 0
= x < 0, x < \(\frac{1}{6}\) (solution)
Case 2 (+, +) = x > 0, 6x - 1 > 0 = x > 0
x > \(\frac{1}{6}\)
Combining solutions in cases (1) and (2)
= x > 0, x < \(\frac{1}{6}\) = 0 < x < \(\frac{1}{6}\)
N2,050
N2,600
N3,100
N3,450
Correct answer is A
360\(^o\) - (60\(^o\) + 60\(^o\) + 67 + 50 = 237\(^o\))
360\(^o\) - 237 = 130\(^o\)
B. Salary = \(\frac{123}{360} X \frac{N6000}{1}\)
= N2,050
Find the simple interest rate percent annum at which N1000 accumulates to N1240 in 3 years.
6%
8%
10%
12%
Correct answer is B
I = \(\frac{PRT}{100}\) = 1 = 1240 - 1000 = 240
R = \(\frac{240 \times 100}{100 \times 3}\) = 8%
60\(\sqrt{3m}\)
30\(\sqrt{3m}\)
20\(\sqrt{3m}\)
10\(\sqrt{3m}\)
Correct answer is B
h = 30 tan 60
= 30\(\sqrt{3}\)