How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Find the equation of the line through the points (5, 7) parallel to the line 7x + 5y = 12.
5x + 7y = 120
7x + 5y = 70
x + y = 7
15x + 17y = 90
Correct answer is B
Equation through (5,7) parallel to the line
7x + 5y = 12
5y = 7x + 12
y = \(\frac{-7x}{5} + \frac{12}{5}\)
Gradient = \(\frac{-7}{5}\)
Required equation = \(\frac{y - 7}{x - 5} = \frac{-7}{5}\)
i.e. 5y - 35 = -7x + 35
5y + 7x = 70
| Marks | 0 | 1 | 2 | 3 | 4 | 5 |
| Frequency | 7 | 4 | 18 | 12 | 8 | 11 |
The table gives the distribution of marks obtained by a number of pupils in a class test. Using this information, Find the median of the distribution
4
3
1
2
Correct answer is B
Median is \(\frac{n}{2} = \frac{6}{2}\)
= 3
Median = 3
| Age in years | 7 | 8 | 9 | 10 | 11 |
| No of pupils | 4 | 13 | 30 | 44 | 9 |
The table above shows the number of pupils in a class with respect to their ages. If a pie chart is constructed to represent the age, the angle corresponding to 8 years old is
48.6°
56.3°
46.8°
13°
Correct answer is C
Total number of pupils : 4 + 13 + 30 + 44 + 9 = 100
The number of 8 - year olds = 13
The angle represented by the 8-year olds on the pie chart = \(\frac{13}{100} \times 360°\)
= 46.8°
Find the gradient of the line passing through the points (-2, 0) and (0, -4)
2
-4
-2
4
Correct answer is C
Given (-2, 0) ans (0, -4).
Gradient = \(\frac{y_2 - y_1}{x_2 - x_1}\)
= \(\frac{-4 - 0}{0 - (-2)}\)
= \(\frac{-4}{2}\)
= -2
In this fiqure, PQ = PR = PS and SRT = 68\(^o\). Find QPS
136\(^o\)
124\(^o\)
112\(^o\)
68\(^o\)
Correct answer is A
Since PQRS is quadrilateral
2y + 2x + QPS = 360\(^o\)
i.e. (y + x) + QPS = 360\(^o\)
QPS = 360\(^o\) - 2 (y + x)
But x + y + 68\(^o\) = 180\(^o\)
There; x + y = 180\(^o\) - 68\(^o\) = 112\(^o\)
QPS = 360 - 2(112\(^o\))
= 360\(^o\) - 224 = 136\(^o\)