How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
\(\frac{5}{12}\)
\(\frac{1}{3}\)
\(\frac{3}{4}\)
\(\frac{7}{12}\)
Correct answer is D
Coca-Cola = 10 bottles, Fanta = 8 bottles, Spirite = 6 bottles
Total = 24
P(Coca-Cola) = \(\frac{10}{24}\); P(not Coca-Cola)
1 - \(\frac{10}{24}\)
\(\frac{24 - 10}{24} = \frac{14}{24} = \frac{7}{12}\)
What is the product of \(\frac{27}{5}\), \((3)^{-3}\) and (\(\frac{1}{5})^{-1}\)?
5
3
1
\(\frac{1}{25}\)
Correct answer is C
\(\frac{27}{5} \times 3^{-3} \times \frac{(1)^{-1}}{5}\)
= \(\frac{27}{5} \times \frac{1}{3^3} \times \frac{1}{\frac{1}{5}}\)
\(\frac{27}{5}\) x \(\frac{1}{27}\) x \(\frac{5}{1}\) = 1
The angle of a sector of a circle radius 10.5 cm is 48\(^o\). Calculate the perimeter of the sector.
25.4cm
25.4cm
25.6cm
29.8cm
Correct answer is D
The lenght of Arc AB = \(\frac{Q}{360}\) 2\(\pi\)r
= \(\frac{48}{360}\) x 2\(\frac{22}{7}\) x 10.5 = \(\frac{48}{360}\) x 2\(\frac{22}{7}\) x \(\frac{21}{2}\)
= \(\frac{4 \times 22 \times 3}{30} \times \frac{88}{10}\) = 8.8cm
Perimeter = 8.8 + 2r = 8.8 + 2r
= 8.8 + 2(10.5)
= 8.8 + 21
= 29.8cm
30\(^o\)
60\(^o\)
112.5\(^o\)
157.5\(^o\)
Correct answer is D
Rice = 75g, Margarine = 40g, Meat = 105g
Bread = 20g
Total = 240
Angle of sector represented by meat
= \(\frac{105}{240} \times \frac{360^o}{1}\)
= 157.5
Simplify \(\frac{324 - 4x^2}{2x + 18}\)
2(x - 9)
2(9 + x)
81 - x\(^2\)
-2(x - 9)
Correct answer is D
234 - 4x\(^2\) = 18\(^2\) - (2x)\(^2\) = (18 - 2x)(18 + 2x)
2x + 18 = 2x + 18 = (2x + 18)
18 - 2x = 2(a - x) or -2(x - a)