How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
180
60
25
20
Correct answer is D
Let x rep. numbers of boys that can work at \(\frac{5}{4}\) the rate at
which the 10 girls work
For 1 hrs, x boys will work for \(\frac{\frac{1}{5} \times 10}{4}\)
x = \(\frac{5}{4}\) x 10
= 8 boys
8 boys will do the work of ten girls at the same rate
4 + 8 = 12 bous cut the field in 5 hrs for 3 hrs,
\(\frac{12 \times 5}{3}\) boys will be needed = 20 boys.
0
0.9
1.1
1.2
Correct answer is C
\(\frac{0.021741 \times 1.2047}{0.023789}\) = \(\frac{0.0255 \times 1.2}{0.024}\) (to 216)
= \(\frac{0.0264}{0.024}\) = 1.1
x < 11
x < -1
x > 6
x > 11
Correct answer is D
\(\frac{1}{3}\) (x + 1) - 1 > \(\frac{1}{5}\)(x + 4) = \(\frac{x + 1}{3} - 1\) > \(\frac{x + 4}{5}\)
\(\frac{x + 1}{3} - \frac{x + 4}{5} -1\) > 0
= \(\frac{5x + 5 - 3x - 12}{15}\)
2x - 7 > 15
2x > 22 = x > 11
Find all median of the numbers 89, 141, 130, 161, 120, 131, 131, 100, 108 and 119
131
125
123
120
Correct answer is B
Arrange in ascending order
89, 100, 108, 119, 120,130, 131, 131, 141, 161
Median = \(\frac{120 + 130}{2}\) = 125
Factorise (4a + 3) \(^2\) - (3a - 2)\(^2\)
(a + 1)(a + 5)
(a - 5)(7a - 1)
(a + 5)(7a + 1)
a(7a + 1)
Correct answer is C
[(4a + 3) \(^2\) - (3a - 2)\(^2\) = a\(^2\) - b\(^2\) = (a + b) (a - b)
= [(4a + 3) + (3a - 2)] [(4a + 3) - (3a - 2)]
= [4a + 3 + 3a - 2] [4a + 3 - 3a + 2]
= (7a + 1)(a + 5)
(a + 5) (7a + 1)