Mathematics questions and answers

Mathematics Questions and Answers

How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.

446.

In a committee of 5, which must be selected from 4 males and 3 females. In how many ways can the members be chosen if it were to include 2 females?

A.

144 ways

B.

15 ways

C.

185 ways

D.

12 ways

Correct answer is D

For the committee to include 2 females, we must have 3 males, so that there should be 5 members.

That is, \(^4C_3 \times ^3C_2\)

= \(\frac{4!}{(4 - 3)! 3!} \times \frac{3!}{(3 - 2)! 2!}\)

= 4 × 3 = 12 ways

447.

If the universal set μ = {x : 1 ≤ x ≤ 20} and
A = {y : multiple of 3}
B = |z : odd numbers}
Find A ∩ B

A.

{1, 3, 6}

B.

{3, 5, 9, 12}

C.

{3, 9, 15}

D.

{2, 3, 9}

Correct answer is C

μ = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20} A = {3, 6, 9, 12, 15, 18} B = {1, 3, 5, 7, 9, 11, 13, 15, 17, 19} A ∩ B = {3, 9, 15}

448.

If the 3rd and 7th terms of a G.P are 9 and 1/9 respectively. Find the common ratio.

A.

\(\frac{1}{3}\)

B.

\(\frac{1}{9}\)

C.

\(\frac{2}{3}\)

D.

\(\frac{2}{9}\)

Correct answer is A

\(T_n = ar^{n - 1}\) (terms of a G.P)

\(T_3 = ar^2 = 9\) ... (i)

\(T_7 = ar^6 = \frac{1}{9}\) ... (ii)

Divide (i) by (ii);

\(\frac{ar^6}{ar^2} = \frac{\frac{1}{9}}{9}\)

\(r^4 = \frac{1}{81}\)

\(r^4 = (\frac{1}{3})^4\)

\(r = \frac{1}{3}\)

449.

Find the probability that a number selected at random from 21 to 34 is a multiple of 3

A.

\(\frac{3}{11}\)

B.

\(\frac{2}{9}\)

C.

\(\frac{5}{14}\)

D.

\(\frac{5}{13}\)

Correct answer is C

S = {21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34}

n(S) = 14

multiples of 3 = {21, 24, 27, 30, 33}

n(multiples of 3) = 5

Prob( picking a multiple of 3) = 5/14

450.

Integrate \(\int (4x^{-3} - 7x^2 + 5x - 6) \mathrm d x\).

A.

\(-2x^{-2} - \frac{7}{3}x^3 + \frac{5}{2} x^2 - 6x\)

B.

\(2x^2 + \frac{7}{3} x^3 - 5x + 6\)

C.

\(12x^2 + 14x - 5\)

D.

\(-12x^{-4} - 14x + 5\)

Correct answer is A

\(\int (4x^{-3} - 7x^2 + 5x - 6) \mathrm d x\)

= \(\frac{4x^{-3 + 1}}{-3 + 1} - \frac{7x^{2 + 1}}{2 + 1} + \frac{5x^{1 + 1}}{1 + 1} - 6x\)

= \(-2x^{-2} - \frac{7}{3} x^3 + \frac{5}{2} x^2 - 6x\)