How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
43.7% loss
13.2% gain
13.2% loss
43.7% gain
Correct answer is C
Cost price of the car = N 1,250.00
Selling price = N 1,085.00
Loss = N (1250 - 1085)
= N 165.00
% loss = \(\frac{165}{1250} \times 100%\)
= 13.2% loss
1080°
1260°
2160°
1800°
Correct answer is B
Since each interior angle = 140°;
Each exterior angle = 180° - 140° = 40°
Number of sides of the polygon = \(\frac{360°}{40°}\)
= 9
Sum of angles in the polygon = 140° x 9
= 1260°
26°
13°
80°
102°
Correct answer is D
< BAC = \(\frac{130}{2}\) (angle subtended at the centre)
< BAC = 65°
Also, x = 26° (theorem)
y = 65° - 26° = 39°
< AOC = 180° - (39° + 39°)
= 102°
If \(P = (\frac{Q(R - T)}{15})^{\frac{1}{3}}\), make T the subject of the formula.
\(T = \frac{15R - Q}{P^3}\)
\(T = R - \frac{15P^3}{Q}\)
\(T = \frac{R - 15P^3}{Q}\)
\(T = \frac{R + P^3}{15Q}\)
Correct answer is B
\(P = (\frac{Q(R - T)}{15})^{\frac{1}{3}}\)
\(P^3 = \frac{Q(R - T)}{15}\)
\(Q(R - T) = 15P^3\)
\(R - T = \frac{15P^3}{Q}\)
\(T = R - \frac{15P^3}{Q}\)
24°
56°
127°
156°
Correct answer is D
\(\tan \theta = \frac{9}{20} = 0.45\)
\(\theta = \tan^{-1} (0.45) \)
= 24.23°
\(\therefore\) The bearing of Y from X = 180° - 24.23°
= 155.77°
= 156° (to the nearest degree)