Physics questions and answers

Physics Questions and Answers

If you want to learn more about the nature and properties of matter and energy or you're simply preparing for a Physics exam, these Physics past questions and answers are ideal for you.

2,551.

A quantity of gas occupies a certain volume when the temperature is -73oC and the pressure is 1.5 atmospheres. If the pressure is increased to 4.5 atmospheres and the volume is halved at the same time, what will be the new temperature of the gas?

A.

573oC

B.

327oC

C.

300oC

D.

110oC

E.

27oC

Correct answer is E

General Gas Law:

\(\frac{P_1 V_1}{T_1}\) = \(\frac{P_2 V_2}{T_2}\)

where T\(_1\) = -73 + 273 = 200k,      T\(_2\) = ?,

V\(_1\) = 1,         V\(_2\) = \(\frac{1}{2V}\),

P\(_1\) = 1.5,      P\(_2\) = 4.5

T\(_2\) = \(\frac{P_2 V_2 T_1}{P_1 V_1}\)

T\(_2\) = \(\frac{4.5 * 1/2 * 200}{1.5 X 1}\)

T\(_2\) → 300k or 27ºC
 

2,553.

A thin aluminum plate has a surface area of 1500m at 20oC. What will be its surface area when it is cooled to -20oC? (Take the linear expansivity of aluminum to be 2.5 x 10-5k-1).

A.

1.503m2

B.

1.500m2

C.

1.498m2

D.

1.497m2

E.

1.490m2

Correct answer is C

\(\beta\) = A2 - A1

2 X 10-5 x 2.5 = \(\frac{A_2 \times 1.5}{1.5 \times (-20 -20)}\)

A2 = 1.498m2

2,554.

A uniform cylindrical block of wood floats in water with one-third of its height above the water level, in a liquid of relative density 0.8, what fraction of its height will be above the liquid level?

A.

\(\frac{1}{6}\)

B.

\(\frac{1}{5}\)

C.

\(\frac{1}{3}\)

D.

\(\frac{4}{5}\)

E.

\(\frac{5}{6}\)

Correct answer is E

Height inside H2O = \(\frac{2}{3}\)

R.d = \(\frac{\text{height inside}H_2O}{\text{height inside liquid}}\)

0.8 = \(\frac{\frac{2}{3}}{X}\)

2,555.

A metal cube of volume 103mm3 is lowered into a measuring cylinder containing water. If the internal cross-sectional area of the cylinder is 1.5 x 102mm2, by how much does the water level rise in the cylinder?

A.

6.67 x 100mm

B.

8.50 x 102mm

C.

1.15 x 103mm

D.

2.50 x 103mm

E.

1.50 x 105mm

Correct answer is A

Height = \(\frac{volume}{area}\)

= Height = \(\frac{10^3}{1.5 \times 10^2}\)

= 6.67mm