Physics questions and answers

Physics Questions and Answers

If you want to learn more about the nature and properties of matter and energy or you're simply preparing for a Physics exam, these Physics past questions and answers are ideal for you.

2,531.

A wire P has half the diameter and half the length of a wire Q of similar material. The ratio of the resistance of P to that of Q is

A.

8 : 1

B.

4 : 1

C.

2 : 1

D.

1 : 1

E.

1 : 4

Correct answer is C

Resistance \(\alpha\) \(\frac{length}{area}\)

\(\frac{R_Q}{R_P}\) = \(\frac{L_QA_P}{L_PA_Q}\)

LQ = 2LP

DQ = 2DP

AP = \(\pi\)\(\frac{(2D_P)^2}{2}\)

= \(\pi\)DP

AQ = \(\pi\)\(\frac{(D_P)^2}{2}\)

= \(\frac{1}{4}\)\(\pi\)DP

therefore, \(\frac{R_Q}{R_P}\) = \(\frac{2L_P \times \pi D_P}{L_P \times \frac{1}{4} \pi D_P}\)

= 2 : 1

2,532.

Which of the following will convert a milliammeter to a voltmeter?

A.

low series resistance

B.

low parallel resistance

C.

high series resistance

D.

high parallel resistance

E.

parallel resistance equal to milliammeter resistance

Correct answer is C

No explanation has been provided for this answer.

2,533.

A cell gives a current of 0.15A through a resistance of 8\(\Omega\) and 0.3A. When the resistance is changed to 3\(\Omega\) the internal resistance of the cell is

A.

0.05\(\Omega\)

B.

1.00\(\Omega\)

C.

1.50\(\Omega\)

D.

2.00\(\Omega\)

E.

2.50\(\Omega\)

Correct answer is D

The E.M.F of a circuit is given by 

\(E=I(R+r)\)

Hence, E = 0.15(8+r)  = 0.3(3+r)

1.2 + 0.15r = 0.9 + 0.3r

1.2 - 0.9 = 0.3r - 0.15r

0.3 = 0.15r

r = \(\frac{0.3}{0.15}\)

r = 2\(\Omega\)

2,534.

Which of the following methods CANNOT be used to produce a steel magnet? The

A.

passing of an electric current through a solenoid

B.

repeated stroking of the specimen with a magnet

C.

repeated stroking of the specimen in opposite directions with magnets

D.

heating of the specimen

E.

hammering of the specimen in the earth's magnetic field

Correct answer is D

No explanation has been provided for this answer.

2,535.

If the distance between two stationary charged particle is doubled, the magnitude of the electro-static force between them will be

A.

doubled

B.

halved

C.

a quarter of its former value

D.

unchanged

E.

four times the original value

Correct answer is C

F \(\alpha\) \(\frac{1}{d^2}\)

F x d2 = constant

F1 x (d1)2 = F2 x (d2)2

d2 = 2d1

F1 x (d1)2 = F2 x (2d1)2

F2 = \(\frac{1}{4}\)F1