Physics questions and answers

Physics Questions and Answers

If you want to learn more about the nature and properties of matter and energy or you're simply preparing for a Physics exam, these Physics past questions and answers are ideal for you.

4,027.

On a fairly cool rainy day when the temperature is 20oC, the length of a steel railroad track is 20m. What will be its length on a hot a dry day when the temperature is 40oC?
[coefficient of linear expansion of steel = 11 x 10-6K-1]

A.

20.013m

B.

20.009m

C.

20.004m

D.

20.002m

Correct answer is C

The increase in length of the steel rail is given by
= α 10
= 11 x 10-6 x 20 x (40 -20)
= 11 x 10-6 x 20 x 20
= 4.4 x 10-3
∴ Final length will be original length plus increase in length
= 20 + 4.4 x 10-3
= 20 + 0.0044
= 20.0044m

4,028.

An open pipe closed at one end produces its first fundamental note. If the velocity of sound in air is P and t the length of the pipe, the frequency of the note is

A.

2v/t

B.

v/5t

C.

v/4t

D.

v/2t

Correct answer is C

In vibration in a closed pipe/tube as shown in the figure, fundamental note is produced at the first position of resonance. When the length of the air column L = λ/4; => λ = 4L. Since the open end of the tube is taken as an antinode; and closed end as the node.
Thus the associated frequency is given by
f = V/λ = V/4L
∴ f = V/4L

4,029.

Thermal equilibrium between two object exist when

A.

the temperature of both objects are equal

B.

the quantity of heat of both objects is the same

C.

the heat capacities of both objects are the same

D.

one object losses heat continuously to the other

Correct answer is A

Two thermal objects are said to be in a thermal equilibrium when the temperature of both objects are equal. Generally, heat flows from an object at a higher temperature to the one at a lower temperature until both temperature are the same, during which the two bodies are said to be in thermal equilibrium

4,030.

By what factor will the size of an object placed 10cm from a convex lens be increased if the image is seen on a screen placed 25cm from the lens?

A.

15.0

B.

2.5

C.

1.5

D.

0.4

Correct answer is B

Form the lens formula = 1/U + 1/V = 1/f
=> 1/10 + 1/25 = 1/f;
∴ (5 + 2) / 50 = 1/f
∴ f = 50/7cm
since the image is observed on a screen, it is a real image. Thus magnification
M = f/U-f

= __50/7
10 - 50/7

∴ M = 50/7
20/7

= 50/7 x 7/20 = 2.5