Physics questions and answers

Physics Questions and Answers

If you want to learn more about the nature and properties of matter and energy or you're simply preparing for a Physics exam, these Physics past questions and answers are ideal for you.

4,036.

If an object just begins to slide on a surface inclined at 30o to the horizontal,the coefficient of friction is

A.

√3

B.

√3/2

C.

1/√2

D.

1/√3

Correct answer is D

A body sliding down a plane inclined at 30o to the horizontal, has coefficient of friction
= tan 30o = 1/√3

4,037.

A hose of cross-sectional area 0.5m2 is used to discharge water from a water tanker at a velocity of 60ms-1 in 20s into a container. If the container is filled completely, the volume of the container is

A.

240m3

B.

600m 3

C.

2400m 3

D.

6000m3

Correct answer is B

Vol = cross-sectional area x length
∴ vol. of water disharged per sec
= 60ms-1 x 0.5m
= 30m3 5-1
=> Vol. of water discharged in the said 20s
= 30m3 x 20 = 600m3
∴ vol. of the container = 600m3

4,038.

The length of piece of glass block was measured by means of a vernier calliper as shown above. The length of the glass block is

A.

1.63 cm

B.

1.64 cm

C.

1.65 cm

D.

1.66 cm

Correct answer is B

No explanation has been provided for this answer.

4,039.

A test tube of radius 1.0cm is loaded to 8.8g. If is placed upright in water, find the depth to which it would sink

A.

2.8cm

B.

5.2cm

C.

25.5cm

D.

28.0cm

Correct answer is A

Pressure = F/A = pgh, where p = density, h = depth and g = 10ms-2
But F = P x A
∴ Force exerted by the load test tube = cross-sectional Area x Pressure
i.e F = A x pgh

∴ h = F_
A x pg

 

= mg
A x P x g

 

 

= 8.8 x 10-3 x 10
πr2 x p x g

 

 

= _8.8 x 10-3 x 10
π x (1.0-2)2 x 1000 x 10


= 0.028m or 2.8cm

 

4,040.

On top of a spiral spring of the force constant 500Nm-1 is placed a mass of 5 x 10-3 kg. If the spring is compressed downwards by a length of 0.02m and then released, calculate the height to which the mass is projected

A.

8 m

B.

4 m

C.

2 m

D.

1 m

Correct answer is C

K = 500Nm-1; M = 5 x 10-3kg; e = 0.02m;
g = 10ms-2. The elastic potential energy stored in the compressed spring is given by = 1/2Ke2, and the energy is transformed into gravitational potential energy = mgh, thus from the principle of energy conversion, we have that mgh = 1/2Ke2
5 x 10-3 x 10 x h = 1/2 x 500 x (0.02)2
∴ h = 1 x 500 x 0.02 x 0.022 x 5 x 10-3 x 10
= 5 x 2 x 0.02___10-1
= 10 x 0.02 x 10 = 2
∴ h = 2m