An ammeter of resistance 1.0 $\Omega$ has a full-scale deflection of 50mA. Determine the resultant full-scale deflection of the meter when a shunt of 0.0111 $\Omega$ is connected across its terminals.

400mA

450mA

500mA

550mA

Correct answer is A

V = 0.1 x 50 x 10^-3 = 5 x 10^-3volts

R_T = $\frac{0.1 \times 0.0111}{0.1 + 0.0111}$

= 9.99 x 10^-3 $\Omega$

V = IR $\Rightarrow$ I

= $\frac{5 \times 10^{-3}}{9.9 \times 10^{-3}}$

= 0.5A ; = 500mA

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