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A man walks 1km due east and then 1km due north. His disp...

A man walks 1km due east and then 1km due north. His displacement is

A.

1 km N15^oE

B.

1 km N30^oE

C.

$\sqrt 2$ km N 45^oE

D.

$\sqrt 2$ km N 60^oE

E.

2km N 75^oE

View answer & explanation

Correct answer is C

R = $\sqrt{1^2 + 1^2}$ = $\sqrt{2km}$

$\theta$ = tan^-1 $\frac{(1)}{1}$ = 45^oC

= $\sqrt 2$ km N 45^oE

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