In the diagram P, Q, R, S are points on the circle RQS = 30o. PRS = 50o and PSQ = 20o. What is the value of xo + yo?
260o
130o
100o
80o
Correct answer is B
Draw a line from P to Q
< PQS = < PRS (angle in the sam segment)
< PQS = 50o
Also, < QSR = < QPR(angles in the segment)
< QPR = xo
x + y + 5= = 180(angles in a triangle)
x + y = 180 - 50
x + y = 130o
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