a+ba−b
1a2−b2
a−ba+b
a2 - b2
Correct answer is B
1p=a2+2ab+b2a−b
1q=a+ba2−2ab+b2
1p=(a+b)2a−b
1q=a+b(a−b)2
∴
\frac{p}{q} = p \times \frac{1}{q} = \frac{a - b}{(a + b)^{2}} \times \frac{a + b}{(a - b)^{2}}
= \frac{1}{(a + b)(a - b)}
= \frac{1}{a^{2} - b^{2}}
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