\(\begin{array}{c|c}
x & 0 & 1\frac{1}{4} &...
x011424y3512
The table given shows some values for a linear graph. Find the gradient of the line
1
2
3
4
Correct answer is B
Ler: (x1, y1) = (0, 3)
(x2, y2) = (54,112)
Using gradient, m = y2−y2x2−x1
= 112−354−0
= 11−62+54
= 5+54
= 52×45
= 2
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