In the diagram above, O is the centre of a circle NST. |N...
In the diagram above, O is the centre of a circle NST. |NT| = |ST| and ∠NTS = 36°. Find the measure of the angle marked t.
\(72^0\)
\(54^0\)
\(36^0\)
\(108^0\)
Correct answer is C
t = ∠NTS (the angle between a tangent and a chord is equal to the angle in the alternate segment).
Therefore, t = 36°
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