2(x2−1)
2x2+4x−1
2x2+6x−1
3(x2−1)
Correct answer is A
f(x)=2x2−3;g(x)=x+1
gof(x)=g(2x2−3)
= 2x2−3+1=2x2−2=2(x2−1)
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