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Given that $f(x) = 2x^{2} - 3$ and $g(x) = x + 1$ where ...

Given that $f(x) = 2x^{2} - 3$ and $g(x) = x + 1$ where $x \in R$ . Find g o f(x).

A.

$2(x^{2} - 1)$

B.

$2x^{2} + 4x - 1$

C.

$2x^{2} + 6x - 1$

D.

$3(x^{2} - 1)$

View answer & explanation

Correct answer is A

$f(x) = 2x^{2} - 3; g(x) = x + 1$

$g o f(x) = g (2x^{2} - 3)$

= $2x^{2} - 3 + 1 = 2x^{2} - 2 = 2(x^{2} - 1)$

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