2x2−9x+15=0
2x2−9x+13=0
2x2−9x−13=0
2x2−9x−15=0
Correct answer is B
Note: Given the sum of the roots and its product, we can get the equation using the formula:
x2−(α+β)x+(αβ)=0. This will be used later on in the course of our solution.
Given equation: 2x2−5x+6=0;a=2,b=−5,c=6.
α+β=−ba=−(−5)2=52
αβ=ca=62=3
Given the roots of the new equation as (α+1) and (β+1), their sum and product will be
(α+1)+(β+1)=α+β+2=52+2=92=−ba
(α+1)(β+1)=αβ+α+β+1=3+52+1=132=ca
The new equation is given by: x2−(−ba)x+(ca)=0
= x2−(92)x+132=2x2−9x+13=0
The roots of the quadratic equation 2x2−5x+m=0 are α and β, where m is...
Solve: 4sin2θ + 1 = 2, where 0º < θ < 180º...
Given that M is the midpoint of T (2, 4) and Q (-8, 6), find the length of MQ . ...
Which of the following is the same as \sin (270 + x)°?...
Simplify: ^{n}C_{r} ÷ ^{n}C_{r-1}...
Evaluate \int_{0}^{2} (8x - 4x^{2}) \mathrm {d} x....
How many ways can 12 people be divided into three groups of 2, 7 and 3 in that order? ...
Find the equation of a circle with centre (-3, -8) and radius 4\sqrt{6}...