24ms−2
18ms−2
12ms−2
10ms−2
Correct answer is C
ds(t)dt=v(t) and dv(t)dt=a(t)
∴
\frac{\mathrm d (24t - 6t^{2})}{\mathrm d t} = 24 - 12t = a(t)
a(1) = 24 - 12(1) = 24 - 12 = 12ms^{-2}
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