f−1:x→2x+3x−1,x≠1
f−1:x→x+3x+2,x≠−2
f−1:x→x−12x+3,x≠−32
f−1:x→x−2x+3,x≠−3
Correct answer is A
f(x)=x+3x−2
f(y)=y+3y−2
Let f(y) = x,
x=y+3y−2
x(y−2)=y+3
xy−y=2x+3⟹y(x−1)=2x+3
y=2x+3x−1
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