f(x)=x3−1x4+2
f(x)=x3+1x4+2
f(x)=x3−1x4−2
f(x)=x3+1x4−2
Correct answer is B
dydx=3x2−4x5=3x2−4x−5
y=∫(3x2−4x−5)dx
y=x3+1x4+c
f(1) = 4; 4=13+114+c⟹4=2+c
c=2
f(x)=x3+1x4+2
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