\(-\frac{896x^6}{9}\)
\(-\frac{896x^5}{9}\)
\(-\frac{896x^5}{27}\)
\(-\frac{896x^6}{27}\)
Correct answer is C
rth term of a binomial expansion =\(^nC_r-1 a^{n-(r-1)}b^{r-1}\)
\(n = 10,r = 6 \therefore r-1=5\)
6th term =\(^{10}C_5 1^{10} - 5 (-\frac{2}{3}x)^5\)
\(=252*1*-\frac{32x^5}{243}=-\frac{896x^5}{27}\)
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