WAEC Past Questions and Answers - Page 1146

5,726.

The mean age of 15 pupils in a class is 14.2 years. One new pupil joined the class and the mean changed to 14.1 years. Calculate the age of the new pupil.

A.

12.4 years

B.

12.6 years

C.

13.2 years

D.

14.1 years

Correct answer is B

\(Mean = \frac{\text{sum of ages}}{\text{no of pupils}}\)

Let the sum of the ages of the 15 pupils be x and the sum of the 16 pupils be y.

\(\frac{x}{15} = 14.2 \implies x = 14.2 \times 15 = 213\)

\(\frac{y}{16} = 14.1 \implies y = 14.1 \times 16 = 225.6\)

\(\text{Age of new pupil} = 225.6 - 213 = 12.6\)

5,727.

Which of the following is an item of prime cost?

A.

Royalities payable

B.

Factory salaries

C.

Depreciation of plant

D.

Rent of factory building

Correct answer is A

No explanation has been provided for this answer.

5,728.

Find the equation of the tangent to the curve \(y = 4x^{2} - 12x + 7\) at point (2, -1).

A.

y + 4x - 9 = 0

B.

y - 4x - 9 = 0

C.

y - 4x + 9 = 0

D.

y + 4x + 9 = 0

Correct answer is C

\(y = 4x^{2} - 12x + 7\)

\(\frac{\mathrm d y}{\mathrm d x} = 8x - 12\)

At x = 2, y = 8(2) - 12 = 4

Equation of the tangent to the curve: \(y - (-1) = 4(x - 2)\)

\(y + 1 = 4x - 8 \implies y - 4x + 1 + 8 = y - 4x + 9 = 0\)

5,729.

Find the axis of symmetry of the curve \(y = x^{2} - 4x - 12\).

A.

x = -2

B.

y = -2

C.

x = 2

D.

y = 2

Correct answer is C

The vertical line \(x = \frac{-b}{2a}\) is the axis of symmetry of the curve.

\(y = x^{2} - 4x - 12\)

\(\text{Axis of symmetry} = x = \frac{-(-4)}{2(1)} = \frac{4}{2} = 2\)

5,730.

Opening creditors was N65,000, closing creditors was N41,000. Credit purchases was N200,000 and discount received N3,000. How much was paid to creditors?

A.

₦262,000

B.

₦224,000

C.

₦221,000

D.

₦176,000

Correct answer is C

No explanation has been provided for this answer.