y + 4x - 9 = 0
y - 4x - 9 = 0
y - 4x + 9 = 0
y + 4x + 9 = 0
Correct answer is C
y=4x2−12x+7
dydx=8x−12
At x = 2, y = 8(2) - 12 = 4
Equation of the tangent to the curve: y−(−1)=4(x−2)
y+1=4x−8⟹y−4x+1+8=y−4x+9=0
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