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Find the equation of the tangent to the curve \(y = 4x^{2} -...

Find the equation of the tangent to the curve y=4x212x+7 at point (2, -1).

A.

y + 4x - 9 = 0

B.

y - 4x - 9 = 0

C.

y - 4x + 9 = 0

D.

y + 4x + 9 = 0

Correct answer is C

y=4x212x+7

dydx=8x12

At x = 2, y = 8(2) - 12 = 4

Equation of the tangent to the curve: y(1)=4(x2)

y+1=4x8y4x+1+8=y4x+9=0