WAEC Past Questions and Answers - Page 2663

13,311.

Find the next three terms of the sequence; 0, 1, 1, 2, 3, 5, 8...

A.

13, 19, 23

B.

9, 11, 13

C.

11, 15, 19

D.

13, 21, 34

Correct answer is D

No explanation has been provided for this answer.

13,312.

The relation y = x2 + 2x + k passes through the point (2,0). Find the value of k

A.

- 8

B.

- 4

C.

4

D.

8

Correct answer is A

Y = x2 + 2x + k (given)

y = o when x = 2

thus 0 = 22 + 2 x 2 + k

0 = 4 + 4 + k

given k = -8

13,313.

A bag contains 5 red and 4 blue identical balls. Id two balls are selected at random from the bag, one after the other, with replacement, find the probability that the first is red and the second is blue

A.

\(\frac{2}{9}\)

B.

\(\frac{5}{18}\)

C.

\(\frac{20}{81}\)

D.

\(\frac{5}{9}\)

Correct answer is C

n(red balls) = 5

n(blue balls) = 4

n(\(\iff\)) = 9

Hence, prob (R1, B2)

= \(\frac{5}{9} \times \frac{4}{9}\)

= \(\frac{20}{81}\)

13,314.

In the diagram, O is the centre of the circle, < QPS = 100o, < PSQ = 60o and < QSR. Calculate < SQR

A.

20o

B.

40o

C.

60o

D.

80o

Correct answer is A

In the diagram, < RPQ = 80o(angles in same segment)

< SPR = 100o - < RPQ

= 100 - 80

= 20o

< SQR = < SPR = 20o (same reason as above)

< SQR = 20o

13,315.

Simplify \(\frac{(p - r)^2 - r^2}{2p^2 - 4pr}\)

A.

\(\frac{1}{2}\)

B.

p - 2r

C.

\(\frac{1}{p - 2r}\)

D.

\(\frac{2p}{p - 2r}\)

Correct answer is A

\(\frac{(p - r)^2 - r^2}{2p^2 - 4pr}\)

= \(\frac{(p - r)(p - r) - r^2}{2p^2 - 4pr}\)\

= \(\frac{p^2 - 2pr + r^2 - r^2}{2p(p - 2r}\)

= \(\frac{p^2 - 2pr}{2p(p - 2r)}\)

= \(\frac{p(p - 2r)}{2p(p - 2r)}\)

= \(\frac{1}{2}\)