22o
45o
67o
89o
Correct answer is B
In In the diagram given, \(\alpha\) = 22o (vertically opp. angles), \(\alpha\) = \(\beta\) (alternate angles)
< PSQ + 133o + \(\beta\) = 180o (sum of angles of a \(\Delta\))
< PSQ + 133o + 22o = 180o
< PSQ = 180o - (133 + 22)o
45o
70o
80o
105o
110o
Correct answer is B
In the diagram above, x1 = 50(angles in alternate segment)
x1 = x2(base angles of isos. \(\Delta\))
< UXY + x2 + 50o = 180o(sum of angles on a straight line)
< UXY + 50o + 50o = 180p
< UXY + 100o = 180o
< UXY = 180o - 100o
= 80o
13
14
15
16
Correct answer is B
Median = \(\frac{N}{2}\)th age
= \(\frac{50}{2}\)th age
= 25th age
= 14 years
50
55
60
65
Correct answer is A
Number of students in the club is
10 + 24 + 8 + 5 + 3 = 50
32o
40o
60o
69o
Correct answer is D
sin 60o = x + 0.5 0o(given)
0.8660 = x + 0.5
0.8660 - 0.5 = x
x = 0.3660
cos\(\theta\) = x(given)
cos\(\theta\) = 0.3660
Hence, \(\theta\) = cos-1(0.3660)
= 68.53o
= 69o (nearest degree)