WAEC Past Questions and Answers - Page 2667

13,331.

In the diagram, \(\bar{PF}\), \(\bar{QT}\), \(\bar{RG}\) intersect at S and PG||RG. If < SPQ = 113o and < RSt = 220, find < PSQ

A.

22o

B.

45o

C.

67o

D.

89o

Correct answer is B

In In the diagram given, \(\alpha\) = 22o (vertically opp. angles), \(\alpha\) = \(\beta\) (alternate angles)

< PSQ + 133o + \(\beta\) = 180o (sum of angles of a \(\Delta\))

< PSQ + 133o + 22o = 180o

< PSQ = 180o - (133 + 22)o

45o

13,332.

In the diagram, \(\bar{YW}\) is a tangent to the circle at X, |UV| = |VX| and < VXW = 50o. Find the value of < UXY.

A.

70o

B.

80o

C.

105o

D.

110o

Correct answer is B

In the diagram above, x1 = 50(angles in alternate segment)

x1 = x2(base angles of isos. \(\Delta\))

< UXY + x2 + 50o = 180o(sum of angles on a straight line)

< UXY + 50o + 50o = 180p

< UXY + 100o = 180o

< UXY = 180o - 100o

= 80o

13,333.

\(\begin{array}{c|c}
Age(years) & 13 & 14 & 15 & 16 & 17 \\
\hline
Frequency & 10 & 24 & 8 & 5 & 3
\end{array}\)
Find the median age

A.

13

B.

14

C.

15

D.

16

Correct answer is B

Median = \(\frac{N}{2}\)th age

= \(\frac{50}{2}\)th age

= 25th age

= 14 years

13,335.

If cos \(\theta\) = x and sin 60o = x + 0.5 0o < \(\theta\) < 90o, find, correct to the nearest degree, the value of \(\theta\)

A.

32o

B.

40o

C.

60o

D.

69o

Correct answer is D

sin 60o = x + 0.5 0o(given)

0.8660 = x + 0.5

0.8660 - 0.5 = x

x = 0.3660

cos\(\theta\) = x(given)

cos\(\theta\) = 0.3660

Hence, \(\theta\) = cos-1(0.3660)

= 68.53o

= 69o (nearest degree)