What sum of money will amount to D10,400 in 5 years at 6% simple interest?
D8,000.00
D10,000.00
D12,000.00
D16,000.00
Correct answer is A
A = P + 1
I = A - P
= 10,400 - P
Now using I = \(\frac{P \times T \times R}{100}\)
i.e. 10,400 - P = \(\frac{P \times 5 \times 6}{100}\)
= 100(10,400 - P) = 30P
10(10,400 - P) = 3P
104,000 - 10P = 3P
104,000 - 10P = 3P
104,000 = 3P + 10P
= 104,000 = 13P
P = \(\frac{104,000}{100}\)
P = D8,000
Simplify; \(\frac{3^{n - 1} \times 27^{n + 1}}{81^{n}}\)
32n
9
3n
3n + 1
Correct answer is B
\(\frac{3^{n - 1} \times 27^{n + 1}}{81^{n}}\)
= \(\frac{3^{n - 1} \times 3^{3(n + 1)}}{3^{4n}}\)
= 3\(^{n - 1 + 3n + 3 - 4n}\)
= 3\(^{4n - 4n - 1 + 3}\)
= 32
= 9
On a map, 1cm represent 5km. Find the area on the map that represents 100km2.
2cm2
4cm2
8cm2
8cm2
Correct answer is B
On a map, 1cm represents 5km. Then it follows that 1cm2 represents 25km2. Acm2 represents 100km2. By apparent cross-multiplication, 1cm2 x 100km2 = Acm2x 25km2
therefore A = \(\frac{100}{25}\) = 4cm2
Joseph plays football in Nigeria therefore he is a good footballer
Joseph is a good footballer therefore he is a Nigerian footballer
Joseph is a Nigerian footballer therefore he is a good footballer
Joseph plays good football therefore he is a Nigerian footballer
Correct answer is C
From the venn diagram, Nigeria footballers from a subset of good footballers.
90cm
135cm
180cm
225cm
Correct answer is C
d \(\alpha\) t2
d = t2 k
where k is a constant. d = 45cm, when t = 3s; thus 45 = 32 x t
k = \(\frac{45}{9}\) = 5
thus equation connecting d and t is d = 5t2
when t = 6s, d = 5 x 62
= 5 x 36
= 180cm
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