A train moving at a uniform speed covers 36km in 21 minutes. How long does it take to cover 60km?
35 mins
40 mins
45 mins
90 mins
Correct answer is A
Since 36km in 21 minutes
1km in \(\frac{21}{36}\)minutes
60km in \(\left(\frac{21}{36}\times 60\right)\)minutes = \(\frac{70}{2}\)min
= 35 mins
{3, 9}
{5, 7, 9}
{1}
{1, 11}
Correct answer is C
PI = {1, 7, 15} ; QI = {1, 13, 11}
PI ∩ QI = {1}
the bisector of the angle formed by the lines
the point of intersection of the two lines
A cone, with two intersecting lines as slant height
A circle, with the point of intersection of the two lines as the center
Correct answer is A
No explanation has been provided for this answer.
14.67cm
42.67cm
101.33cm
543.33cm
Correct answer is C
The perimeter of the sector \(=2r+\frac{\theta}{360}\times 2\pi r \\
\Rightarrow 28 + \frac{300}{360} \times \frac{2}{1} \times \frac{22}{7}\times \frac{14}{1} = \frac{220}{3}+28\\
73.133+28=101.33cm\)
77cm2
227cm2
297cm2
374cm2
Correct answer is C
T.S.A of s closed cylinder = \(2\pi r(r+h)\\
=\frac{2}{1}\times \frac{22}{7} \times \frac{7}{2}\left(\frac{7}{2}+\frac{10}{1}\right)=\frac{22}{1}\left(\frac{27}{2}\right)=27\times 11=297cm^2\)