N2.50
N3.20
N6.50
N9.60
Correct answer is A
Power = 100W; Voltage = 240V; Time = 5 hours
Total energy used = Power x time = 100 x 5 = 500wh
converting to kwh, we have
\(\frac{500}{1000} = 0.5kWh \times N5 = N2.50\)
4000V
400V
40V
4V
Correct answer is C
\(N_{p} = 3000 turns\)
\(N_{s} = 500 turns\)
\(E_{p} = 240V_{r.m.s}\)
\(E_{s} = ?\)
\(\frac{N_{s}}{N_{p}} = \frac{E_{s}}{E_{p}}\)
\(\frac{500}{3000} = \frac{E_{s}}{240}\)
\(\implies E_{s} = \frac{240\times500}{3000} = 40V\)
I
II
III
IV
Correct answer is C
No explanation has been provided for this answer.
I, II and III
III only
II only
I only
Correct answer is D
No explanation has been provided for this answer.
6A
4A
2A
1A
Correct answer is C
The resistors are connected both in parallel and series. To calculate the total resistance, we have:
For the parallel connection: \(\frac{1}{R} = \frac{1}{1} + \frac{1}{1}\)
\(\frac{1}{R} = 2 \implies R = 0.5\Omega\)
For the series connection: \(R_{total} = (1 + 0.5)\Omega = 1.5\Omega\)
Recall, \(V=IR\)
\(3 = 1.5I \implies I = \frac{3}{1.5} =2A\)
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