How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Solve: \(log_3 x + log_3 (x - 8) = 2\)
8
6
9
7
Correct answer is C
\(log_3 x + log_3 (x - 8) = 2\)
\(log_3 x(x - 8) = log_39\) since 2 = \(log_39\)
\(log_3\) cancels out
⇒ x(x - 8) = 9
⇒ \(x^2 - 8x = 9\)
⇒ \(x^2 - 8x - 9 = 0\)
⇒ \(x^2 - 9x + x - 9 = 0\)
⇒ x(x - 9) + 1(x - 9) = 0
⇒ (x - 9)(x + 1) = 0
⇒ x = 9 or x = -1
Since we can't have a log of negative numbers,
∴ x = 9.
In the diagram, NR is a diameter, ∠MNR = x° and, ∠SRN = (5x + 20)°. Find the value of 2x.
\(42^0\)
\(35^0\)
\(20^0\)
\(90^0\)
Correct answer is B
∠RMN = 90° (angles in a semicircle is a right angle)
∠SRN = ∠RMN + ∠MNR (ext. angle of a ∆ is equal to the sum of two opp. int. angles)
⇒ 5x + 20 = 90 + x
⇒ 5x - x = 90 - 20
⇒ 4x = 70
x = \(\frac{70}{4}\)
= 17.4°
therefore, 2x = 2\(\times17.5\) = 35°
The price of a shoe was decreased by 22%. If the new price is $27.3. what is the original price.
$62.30
$42.30
$72.00
$35.00
Correct answer is D
Let x = original price
A decrease of 22% = (100-22)% = 78% of the original price.
78% of x = 27.30
= \(\frac{78x}{100} = 27.30\)
78x = 2730
then, x = \(\frac{2730}{78}\)
x = 35
Therefore, the original price of the shoe was $35.00.
Write the name of a triangle with the vertices (1, -3), (6, 2) and (0,4)?
Scalene triangle
Isosceles triangle
Right -angle triangle
Equilateral triangle
Correct answer is B
Let A = (1, -3), B = (6, 2) and C = (0,4)
\(d =\sqrt{ (y_2 - y_1)^2 + (x_2 - x_1)^2}\)
|AB| = \(\sqrt{(2 - (-3))^2 + (6 - 1)^2}\)
= \(\sqrt{(2 + 3)^2 + (6 - 1)^2}\)
= \(\sqrt{5^2 + 5^2}\)
= \(\sqrt{25 + 25}\)
= \(\sqrt50\)
= 5\(\sqrt2\) units
|BC| = \(\sqrt{(4 - 2)^2 + (0 - 6)^2}\)
= \(\sqrt{2^2 + (-6)^2}\)
= \(\sqrt{4 + 36}\)
= \(\sqrt40\)
= 2\(\sqrt10\) units
|AC| = \(\sqrt{(4 - (-3)^2 + (0 - 1)^2}\)
= \(\sqrt{(4 + 3)^2 + (0 - 1)^2}\)
= \(\sqrt{7^2 + (-1)^2}\)
= \(\sqrt{49 + 1}\)
= \(\sqrt50\)
= 5\(\sqrt{2}\) units
Since two sides are equal (|AB| = |AC|), then the triangle is Isosceles.
An equilateral triangle has a side 2 cm. Calculate the height of the triangle.
5cm
\(\sqrt5\)cm
3cm
\(\sqrt{ 3}\)cm
Correct answer is D
using Pythagoras theorem
H = \(\sqrt{ 2^2 - 1^2}\)
= \(\sqrt{ 4 - 1}\)
= \(\sqrt3\)cm
Factorize completely: \(x^2 - (y + z)^2\)
(x - y - z)(x - y - z)
(x + y + z)(x - y - z)
(x + y + z)(x + y - z)
(x + y - z)(x - y + z)
Correct answer is B
\(x^2 - (y + z)^2\)
Using difference of two squares (\(a^2 - b^2 = (a + b)(a - b)|)
⇒ (x + (y + z))(x - (y + z))
⇒ (x + y + z)(x - y - z)
How many students scored at least 3 marks?
44
52
38
18
Correct answer is A
Number of students that scored at least 3 marks = 9 + 1 + 12 + 7 + 5 + 10 = 44
What percentage of the students scored at most 5 marks?
58.5%
63.2%
38.3%
41.5%
Correct answer is A
Number of students that scored at most 5 marks = 12 + 1 + 9 + 6 + 3 = 31
% of student = \(\frac{31}{53} \times 100%\) = 58.5%
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