How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
sin x - x cos x
sin x + x cos x
cos x + x sin x
cos x - x sin x
Correct answer is D
y = x cos x
dy/dx = 1. cos x + x (-sin x)
= cos x - x sin x
Integrate \(\frac{x^2 -\sqrt{x}}{x}\) with respect to x
\(\frac{x^2}{2}-2\sqrt{x}+K\)
\(\frac{2(x^2 - x)}{3x}+K\)
\(\frac{x^2}{2}-\sqrt{x}+K\)
\(\frac{(x^2 - x)}{3x}+K\)
Correct answer is A
\(\int \frac{x^2 -\sqrt{x}}{x} = \int \frac{x^2}{x} - \frac{x^{\frac{1}{2}}}{x}\\
\int x - x^{\frac{-1}{2}}\\
=\left(\frac{1}{2}\right)x^2 - \frac{x^{\frac{1}{2}}}{\frac{1}{2}}+K\\
=\frac{x^2}{2}-2x^{\frac{1}{2}}+K\\
=\frac{x^2}{2}-2\sqrt{x}+K\)
In how many ways can 6 subjects be selected from 10 subjects for an examination
218
216
215
210
Correct answer is D
\(^{10}C_6 = \frac{10!}{(10-6)!6!}=\frac{10!}{4!6!}\\
=\frac{(10\times 9\times 8\times 7 \times 6!)}{4\times 3\times 2\times 1\times 6!}\\
=210\)
| Marks | 3 | 4 | 5 | 6 | 7 | 8 |
| Frequency | 5 | y - 1 | y | 9 | 4 | 1 |
The table above gives the frequency distribution of marks obtained by a group of students in a test. If the total mark scored is 200, calculate the value of y
15
13
11
8
Correct answer is C
Total mark scored = 200
∴200 = 15 + 4y - 4 + 5y + 54 + 28 + 8
200 = 9y + 101
200 - 101 = 9y
99 = 9y
∴y = 11
What is the mean deviation of 3, 5, 8, 11, 12 and 21?
4.7
60
3.7
10
Correct answer is A
No explanation has been provided for this answer.