If you want to learn more about the nature and properties of matter and energy or you're simply preparing for a Physics exam, these Physics past questions and answers are ideal for you.
3.0 x 10\(^{2}\)km\(^{-1}\)
3.0 x 10\(^{3}\)km\(^{-1}\)
5.0 x 10\(^{3}\)km\(^{-1}\)
3.0 x 10\(^{4}\)km\(^{-1}\)
Correct answer is B
\(\Delta\) = \(\frac{\bigtriangleup\theta}{\delta} = \frac{80-20}{0.02}\)
= 3.0 x 10\(^{3}\)km\(^{-1}\)
I, II and III only
I, II, III, and IV
I, II, and IV
II, III, and IV
Correct answer is A
The boiling point of a liquid depends on temperature, atmospheric pressure, and the vapor pressure of the liquid.
When the atmospheric pressure is equal to the vapor pressure of the liquid, boiling will begin
\(\frac{2}{9}\)ºC
\(\frac{4}{9}\)ºC
\(\frac{9}{2}\)ºC
\(\frac{9}{4}\)ºC
Correct answer is B
Using the law of conservation of energy
mc\(\bigtriangleup\theta\) = mgh
\(\bigtriangleup\theta\) = \(\frac{gh}{c} = \frac{10 \times 20}{450} = \frac{4}{9}\)ºC
\(\frac{p_{0}} {5}\)
\(\frac{4p_{0}}{5}\)
p\(_{0}\)
5P\(_{0}\)
Correct answer is D
p\(_{1}\) = P\(_{0}\), V\(_{1}\) = V\(_{0}\), V\(_{2}\) = \(\frac{1}{5}\)V\(_{0}\) P\(_{2}\) = ?
P\(_{1}\)V\(_{1}\) = P\(_{2}\)V\(_{2}\)
P\(_{2}\) = \(\frac{P_{1}V_{1}}{V_{1}}\)
= \(\frac{\not P_{o}V_{o}}{\frac{1}{5}P_{o}}\) = 5\(\not P_{o}\)
When the temperature of a liquid increases, its surface tension
decreases
increases
remains constant
increases then decreases
Correct answer is A
Surface tension decreases by:
* Increasing liquid's temperature
* Adding soap to the liquid