If you want to learn more about the nature and properties of matter and energy or you're simply preparing for a Physics exam, these Physics past questions and answers are ideal for you.
50J
100J
150J
200J
Correct answer is A
Given
m\(_{1}\) = 0.05kg, u\(_{1}\) = 200ms\(^{-1}\), m\(_{2}\) = 0.95kg
K.E = \(\frac{1}{2}\)m\(_{r}\)v\(^{2}\)
m\(_{1}\)u\(_{1}\) = v(m\(_{1}\) + m\(_{2}\)) [law of conversation of momentum]
v = \(\frac{0.05 \times 200}{0.05 + 95}\) = 10ms\(^{-1}\)
K.E = \(\frac{1}{2}\)(1)10\(^{2}\) = 50J
2N
20N
200N
400N
Correct answer is B
Given
m = 10\(^{-2}\)
w = 100rads\(^{-1}\)
F = mw\(^{2}\)r
r = 0.2m
F = ?
= 10\(^{-2}\) x (100)\(^{2}\) x 0.2
= 20N
1:4
2:1
2:3
2:5
Correct answer is C
Given \(\frac{m_{1}}{m_{2}} = \frac{3}{1}\) \(\Rightarrow\) m\(_{1}\) = 3m\(_{2}\)
\(\frac{a_{1}}{a_{2}} = \frac{2}{9}\) = a\(_{1}\) = \(\frac{2a_{2}}{9}\)
\(\frac{F_{1}}{F_{2}}\) = ?
Since F = ma
\(\Rightarrow\) \(\frac{F_{1}}{F_{2}} = \frac{m_{1}a_{1}}{m_{2}a_{2}}\) = \(\frac{(3 \not m_{2})(2 \not a_{2})}{\not m_{2} a_{2} \not a_{3}}\)
\(\frac{F_{1}}{F_{2}} = \frac{2}{3}\) \(\Rightarrow\) 2:3
The inner diameter of a test tube can be measured accurately using a?
micrometer screw gauge
pair of dividers
meter rule
pair of vernier calipers
Correct answer is D
Vernier calipers are also used to measure the internal and external diameters of a tube
beta rays
gamma rays
x-rays
ultra-violet rays
Correct answer is A
Both the electric field and magnetic field affect the β-particles.