Physics questions and answers

Physics Questions and Answers

If you want to learn more about the nature and properties of matter and energy or you're simply preparing for a Physics exam, these Physics past questions and answers are ideal for you.

256.

A man stands 4m in front of a plane mirror. If the mirror is moved 1m towards the man, the distance between him and his new image is?

A.

3m

B.

5m

C.

6m

D.

10m

Correct answer is C

Objects distance (u) = image distance (v)

object distance = 3m

|uv| = 3 + 3 = 6m

257.

The lowest note emitted by a stretched string has a frequency of 40Hz. How many overtones are there between 40Hz and 180Hz?

A.

4

B.

3

C.

2

D.

1

Correct answer is B

f\(_{0}\) = 40H\(_{3}\)

1st overtone = 2f\(_{0}\) = 80H\(_{3}\)

2nd overtone = 3f\(_{0}\) = 120H\(_{3}\)

3rd overtone = 4f\(_{0}\) = 160H\(_{3}\)

4th overtone = 5f\(_{0}\) = 200H\(_{3}\)

\(\therefore\) Number of overtones between 40H\(_{3}\) and 180H\(_{3}\) = 3

258.

If a sound wave goes from a cold air region to a hot air region, its wavelength will?

A.

increase

B.

decrease

C.

decrease then increase

D.

remain constant

Correct answer is A

No explanation has been provided for this answer.

259.

The equation of a wave traveling along the positive x-direction is given by; y = 0.25 x 10\(^{-3}\) sin (500t - 0.025x). Determine the angular velocity of the wave motion. 

A.

0.25 x 10\(^{-3}\)rads\(^{-1}\)

B.

0.25 x 10\(^{-1}\)rads\(^{-1}\)

C.

5.00 x 10\(^{2}\)rads\(^{-1}\)

D.

2.50 x 10\(^{3}\)rads\(^{-1}\)

Correct answer is C

Using y = A sin (wt + 0)

Given y = 0.25 x 10\(^{-3}\)sin (500t - 0.025x)

By comparing, w = 5.00 x 10\(^{2}\)rads\(^{-1}\)

260.

Calculate the mass of ice that would melt when 2kg of copper is quickly transferred from boiling water to a block of ice without heat loss (specific heat capacity of copper = 400Jkg\(^{1}\)k\(^{-1}\), latent heat of fusion of ice = 3.3 x 10\(^{5}\)Jkg\(^{-1}\))

A.

\(\frac{8}{33}\)kg

B.

\(\frac{3.3}{80}\)kg

C.

\(\frac{80}{33}\)kg

D.

\(\frac{3.3}{8}\)kg

Correct answer is A

mc\(\Delta\theta\) = m\(\lambda\)f

2 x 400 (100 - 0) = m(3.3 x 10\(^{5}\))

m = \(\frac{2 \times 400 \times 100}{3.3 \times 10^{5}} = \frac{8}{33}\)kg