Physics questions and answers

Physics Questions and Answers

If you want to learn more about the nature and properties of matter and energy or you're simply preparing for a Physics exam, these Physics past questions and answers are ideal for you.

266.

A solid weighs 10.00N in air, 6N when forcefully immersed in water, and 7.0N when fully immersed in a liquid, X. Calculate the relative density of the liquid X.

A.

\(\frac{5}{3}\)

B.

\(\frac{4}{3}\)

C.

\(\frac{3}{4}\)

D.

\(\frac{7}{10}\)

Correct answer is C

R.D = \(\frac{\text {weigh in air - weigh in liquid X}}{\text {weigh in air - weigh in water}}\)

= \(\frac{10 - 7}{10 - 6} = \frac{3}{4}\)

267.

If the stress on a wire is 10\(^{7}\)NM\(^{-2}\) and the wire is stretched from its original length of 10.00m to 10.05m. The young's modulus of the wire is?

A.

5.0 x 10\(^{-4}\)Nm\(^{-2}\)

B.

5.0 x 10\(^{-5}\)Nm\(^{-2}\)

C.

2.0 x 10\(^{-8}\)Nm\(^{-2}\)

D.

2.0 x 10\(^{9}\)Nm\(^{-2}\)

Correct answer is D

Young's modulus \(\frac{stress}{strain}\)

Strain = \(\frac{e}{l} = \frac{0.05}{10} = \frac{10^{7}}{0.005}\)

2 x 10\(^{9}\)Nm\(^{-2}\)

268.

When the breaks in a car are applied, the frictional force on the tyres is?

A.

a disadvantage because it is in the direction of the motion of the car

B.

a disadvantage because it is in the opposite direction of the motion of the car

C.

an advantage because it is in the direction of the motion of the car

D.

an advantage because it is in the opposite direction of the motion of the car

Correct answer is D

Frictional force opposes motion

269.

A car of mass 800kg attains a speed of 25m/s in 20secs. The power developed in the engine is?

A.

1.25 x 10\(^{4}\)W

B.

2.50x 10\(^{4}\)W

C.

1.25 x 10\(^{6}\)W

D.

2.50 x 10\(^{6}\)W

Correct answer is B

P = \(\frac{mv^{2}}{t} = \frac{800 \times 25 \times 25}{20}\)

2.5 x 10\(^{4}\)W

270.

A ball of mass 0.1kg is thrown vertically upwards with a speed of 10ms\(^{-1}\) from the top of a tower 10m high. Neglecting air resistance, its total energy just before hitting the ground is? (Take g = 10ms\(^{-2}\))

A.

5J

B.

10J

C.

15J

D.

20J

Correct answer is C

m = 0.1kg
u = 10ms\(^{-1}\)
h = 10m
g = 10ms\(^{-2}\)

At h\(_{max}\); v = 0

Using
\(\not v\) = \(\not u\) = \(\not gt\)
\(\not 0\) = \(\not w\) - \(\not 10t\)

v\(^{2}\) = u\(^{2}\) - 2gh
0\(^{2}\) = 10\(^{2}\) - 2 x 10h
20h = 100
h = 5m
Total height = 10 + 5
= 15m
Total energy = mghr = 0.1 x 10 x1 5
= 15J