12.2
12.27
12.9
13.4
Correct answer is B
Class intervalsFClass boundary5−7174.5−9.510−14329.5−14.515−192514.5−19.520−242419.5−24.5 mode = 9.5 + D1D2+D1 x C = 9.5 + 5(32−17)2(32)−17−25 = 9.5 + 7527 = 12.27 ≈ 12.3
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