A notebook of length 15 cm was measured to be 16.8 cm, calculate, correct to two d.p, the percentage error in the measurement.
A.
12.00%
B.
11.71%
C.
10.71%
D.
11.21%
Correct answer is A
Error = 16.8 - 15 = 1.8cm
% error = \(\frac{error}{ Actual value}\times 100%\)
= \(\frac{1.8}{ 15}\times100%\)
= \(0.12\times100%\)
= 12.00%
