Calculate, correct to one decimal place, the acute angle ...
Calculate, correct to one decimal place, the acute angle between the lines 3x - 4y + 5 = 0 and 2x + 3y - 1 = 0.
70.6°
50.2°
39.8°
19.4°
Correct answer is A
tanθ=m1−m21−m1m2
m1=slope of 1st line 4y=3x+5⟹y=34x+54
m1=34
m2=slope of 2nd line3y=1−2x⟹y=13−23x
m2=−23
tanθ=34−(−23)1−((34)(−23))=171212
tanθ=176
\theta \approxeq 70.6°
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